Matematika

Pertanyaan

akar 32- akar 98 + 3 akar 8

1 Jawaban


  • [tex] \sqrt{32} - \sqrt{98} + 3 \sqrt{8} \\ = \sqrt{16 \times 2} - \sqrt{49 \times 2} + 3 \sqrt{4 \times 2} \\ = 4 \sqrt{2} - 7 \sqrt{2} + 6 \sqrt{2} \\ = (4 - 7 + 6) \sqrt{2} \\ = 3 \sqrt{2} [/tex]

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