Matematika

Pertanyaan

ada yang tau caranya gak, kalo tau tolong bantuin yaa tks
ada yang tau caranya gak, kalo tau tolong bantuin yaa tks

2 Jawaban


  • [tex]( {x}^{2} - 4x + 4)(x - 2) \\ = {x}^{3} - {2x}^{2} - {4x }^{2} + 8x + 4x - 8 \\ = {x}^{3} - 6 {x}^{2} + 12x - 8[/tex]

  • [tex]f(x). \: g(x) = (x {}^{2} - 4x + 4)(x - 2) \\ = x {}^{3} - 2x {}^{2} - 4x {}^{2} + 8x + 4x - 8 \\ = x {}^{3} - 6x {}^{2} + 12x - 8[/tex]