Matematika

Pertanyaan

Tan 150° + cos 60° per tan 150° - cos 60°

1 Jawaban

  • (tan(180-30)+1/2)/(tan(180-30)-1/2)
    =(-tan 30+1/2)/(-tan 30-1/2)
    =(-(1/3)√3+1/2)/(-(1/3)√3-1/2)
    =(-(2√3+3)/6) / ((-2/3 - 3)/6)
    =(-2√3+3)/(-2√3 - 3), rasionlkn
    =(-2√3+3)(-2√3+3)/(12-9)
    =(12-12√3+9)/3
    =(21-12√3)/3
    =7-4√3

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