Lim x -> ~ x^2+3x+4/3^2+2x+3
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Lim x -> ~ x^2+3x+4/3^2+2x+3
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1. Jawaban asobri68
x²++3x+4 = (x²/x²)+(3x/x²)+(4/x²)
= (1)+(3/x)+(4/x²)
lim x-->~ ((1)+(3/x)+(4/x²)) = 1 + 0 + 0
= 1
3²+2x+3 = (9/x²)+(2x/x²)+(3/x²)
= (9/x²)+(2/x)+(3/x²)
lim x-->~ ((9/x²)+(2/x)+(3/x²)) = 0 + 0 + 0
= 0
lim x-->~ ((1)+(3/x)+(4/x²)) 1
-------------------------------------- = -- = 0
lim x-->~ ((9/x²)+(2/x)+(3/x²)) 0