Matematika

Pertanyaan

berat tiga buah karung beras
berat tiga buah karung beras

1 Jawaban

  • misal karung 3 = x
    [tex]69 \frac{5}{8} = 23 \frac{5}{6} + 24 \frac{ 3}{4} + x \\ x = 69 \frac{5}{8} - (23\frac{5}{6} + 24 \frac{3}{4} ) \\ x = 69 \frac{5}{8} - (23 \frac{20}{24} + 24 \frac{18}{24} ) \\ x = 69 \frac{5}{8} - 47 \frac{38}{24} \\ x = 69 \frac{5}{8} - 48 \frac{14}{24} \\ x = 68 \frac{15}{24} - 48 \frac{14}{24} \\ x = 20 \frac{1}{24} [/tex]