4 resistor bernilai 6ohm, 10ohm, 6ohm, 12ohm maka hambatan pengganti jika dirangkai paralel adalah?

Diket :
R1 = 6 ohm
R2 = 10 ohm
R3 = 6 ohm
R4 = 12 ohm
paralel

Dit : Hambatan pengganti.....?

Jwb :

1/Rp = 1/R1+1/R2+1/R3+1/R4
1/Rp = 1/6+1/10+1/6+1/12
1/Rp = 10/60+6/60+10/60+5/60
1/Rp = 31/60
Rp = 60/31
Rp = 1,9 ohm

Jadi hambatan penggantinya 1,9 ohm