kak tolong pakai caranya ya kak:)

Rumus volume kerucut:
[tex] v = \frac{1}{3} \times \pi \times {r}^{2} \times t \\ 1232 = \frac{1}{3} \times \frac{22}{7} \times {r}^{2} \times 24 \\ 1232 = \frac{176}{7} \times {r}^{2} \\ 8624 = 176 \times {r}^{2} \\ r = \sqrt{ \frac{8624}{176} } = \sqrt{49} = 7[/tex]

Sisi (s) kerucut:
[tex] {s}^{2} = {t}^{2} + {r}^{2} \\ {s}^{2} = {24}^{2} + {7}^{2} \\ {s}^{2} = 576 + 49 \\ s = \sqrt{625} = 25[/tex]

Rumus luas selimut kerucut:
[tex]Ls = \pi \times r \times s \\ Ls = \frac{22}{7} \times 7 \times 25 \\ Ls = 22 \times 25 \\ Ls = 550 \: {cm}^{2} [/tex]
Jawaban: A

Semoga bermanfaat ^^