Diketahui f(x)=x²-3x-4 dan g(x)=2x+4 tentukan f°g(3)

(fog)(x)
= f(g(x)
= f(2x + 4)
= (2x + 4)^(2) - 3(2x + 4) - 4
= 4x^(2) + 16x + 16 - 6x - 12 - 4
= 4x^(2) + 10x

(fog)(3)
= 4(3)^(2) + 10(3)
= 36 + 30
= 66

f(x) = x² - 3x - 4
g(x) = 2x + 4

(fog)(x) = f(g(x))
(fog)(x) = (2x + 4)² - 3(2x+ 4) - 4
(fog)(x) = (4x²+16x+16) + (-6x-12) - 4
(fog)(x) = 4x² + 10x

(fog) (3) = 4.3² + 10.3
(fog) (3) = 36 + 30
(fog) (3) = 66

Semoga membantu ^-^