Matematika

Pertanyaan

tolong beserta caranya no 23 dan 24
tolong beserta caranya no 23 dan 24

2 Jawaban

  • B3 = 110 (luar berseberangan)
    A4 = 180-110 = 70
    B3 - A4 = 110 - 70 = 40

    5x + 18 + 3x + 10 = 180
    8x + 28 = 180
    8x = 152
    x = 152 : 8 = 19

    BOC = 3×19 + 10 = 57 + 10 = 67
  • 23. B3=A1 → A4=180-110=70
    B3-A4 =110-70=40

    24. 5x+18+3x+10 =180
    8x+28 =180
    8x =152
    x= 152/8=19

    BOC=3x+10= 3(19)+10 =57 +10=67