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Matematika
RiniWiyantdya
Pertanyaan
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1 Jawaban
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1. Jawaban BroJe
sisa = 200 cm - keliling lampion.
keliling alas = 2 × (16 + 12) = 2 × 28 = 56
panjang rusuk tegak lampion =
[tex]4 \times \sqrt{24 {}^{2} + 10 {}^{2} } = 4 \times 26 = 104[/tex]
sisa = 200 - 160 = 40cm
** 24 tinggi limas
** 10 didapat dari 1/2 panjang diagonal alas
** diagonal alas =
[tex] \sqrt{16 {}^{2} + 12 {}^{2} } = \sqrt{400} = 20[/tex]