Jika diketahui jumlah partikel asam sulfida=3,01× 10pangkat 23. Tentukan 1. Mr ? 2.Massa? 3.Mol? 4.volume(0°C, 1 atm)?? Tolong dijwb ya.... Trimk

Mr = 34 > H2S=2+32
m = 17 gram > mr x n =34 x 0,5
n (mol) = 0,5 > N/No = 3,01.10^23/6,02.10^23
volume= 11,193 liter > PV=nRT V=nRT/P R=0,08205

Mr = 2 + 32 =34
Mol = N/No
= 3.01 × 10^23 dibagi 6.02×10^23
= 0.5 mol
Massa = mr× mol = 17 gram
Volume = n × 22.4 ( stp)
= 0.5× 22.4
= 11.2 liter

* 6.02 = bil.avogadro