Tolong bantu yah kak,.... Matematika peminatan nih....

[tex]Vektor[/tex]

25.
vektor a = < 2 3 4 >
vektor b = < 6 7 8 >
AP : PB = 1 : 3

maka p = (1b + 3a) /(1+3)
= (<6 7 8> + <6 9 12>) / (4)
= <12 16 20>/4
= < 3 4 5 > ✔️

26.
a = < 1 2 3 >
b = < 3 2 1 >
S(a,b) = 60°
a • b = |a| |b| cos S(a,b)
= √(1² + 2² + 3²)√(3² + 2² + 1²) (½)
= 7 ✔️

semoga jelas dan membantu