Pada percobaan lempar undi 3 keping uang logam bersama sama sebanyak 600 kali frekuensi harapa muncul paling sedikit dua gambar adalah

n(S) = 2 × 2 × 2 = 8

kejadian munculnya paling sedikit 2 gambar = {(G,G,A), (G,A,G), (A,G,G), (G,G,G)}

n(A) = 4

P(A) = n(A)/n(S)
P(A) = 4/8 = 1/2

fh = P(A) × n
= 1/2 × 600
= 300

Semoga membantu ^^

g = gambar
a = angka
n = 600
2 gambar = (g,g,a), (g,a,g), (g,g,g), (a,g,g)
n (2 gambar) = 4
n (s) = 4/600
gk tau bnr apa salah yah