Deret geometri, 3+6+12+24... S6?
Matematika
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Pertanyaan
Deret geometri, 3+6+12+24... S6?
1 Jawaban
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1. Jawaban Affif17
3 + 6 +12 +24 +48+96
U1+U2+U3+U4+U5+U6
Sn = a(1-r^n)/1-r
S6 = 3(1-(2)^6)/1-(2)
S6 = 3(1-64)/1
S6 = 3(63)/1
S6 = 189/1
S6 = 189
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