soal tentang logaritma. tolong jawab beserta caranya yaa :)

³log5 = m
5log3 = 1/m
7log5 = n
5log7 = 1/n

35 log 15 = 5log15/(5log35)
= 5log(5x3)/(5log (5x7))
= (5log5 + 5log3)/(5log5 + 5log7)
= ( 1 + 1/m) / ( 1 + 1/n )
= (m+1)/m ÷ (n+1)/n
= (m+1)/m x n(n+1)
= n(m+1)/m(n+1)

jawaban : (D)
= n(1+m)/m(1+n)