dibantu ya no.3 nyaa
Matematika
tatata323
Pertanyaan
dibantu ya no.3 nyaa
1 Jawaban
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1. Jawaban nesarsiburian
[tex] \frac{2x + 1}{x - 1} ( \frac{3}{x + 2 } - \frac{1}{x} ) \\ \frac{2x + 1}{x - 1} ( \frac{3x}{ {x}^{2} + 2x } - \frac{x - 2}{ {x}^{2} + 2x } ) \\ \frac{2x + 1}{x - 1} ( \frac{2(x - 1)}{ {x}^{2} + 2x} ) \\ \frac{4x + 2}{ {x}^{2} +2x} = \frac{4 + 2}{1 + 2} = \frac{6}{3} = 2[/tex]