Suatu fungsi dirumuskan dengan f(x)=px+q. Jika f(-6)=17, dan f(4)=-3, maka nilai dari f(3/2) adalah?

mf(-6) = -6p + q = 17
f(4) = 4p + q = -3 (dikurangin, q-nya coret)
= -6p - 4p = 17-(-3)
= -10p = 20
= p = 20/(-10) = -2

f(4) = 4(-2) +q = -3
= -8 + q = -3
= q = -3 + 8 = 5

f(3/2) = -2(3/2) + 5
f(3/2) = -3 + 5 = 2

semoga membantu

F(x) =px+q
F(-6)=p. -6+q
=-6p+q=17
F(4)=p. 4+q
=4p+q=-3
4p+q=-3
-6p+q=17 >>>>kurangkan
Gunakan metode eliminasi

Hasilya
-10p=20
P=20:-10=-2

Substitusi kepersamaan yg diinginkan

4p+q=-3
4.-2+q=-3
=-8+q=-3
Q=5

Jadi nilai f(3/2)
=-2x3/2+5
=-6/2 +5
=2