berapa liter volume3,4 gram gas standar?(arc=12,aro=16

Mapel: Kimia
Kelas: X
Materi: Stoikiometri
Kata Kunci: Persamaan gas ideal

Jawab

CO2
12×16×2
Mr = 32+12= 44

n= m/Mr
n= 3,4/44
n= 0.077mol

V= n×STP
V= 0.077×22,4
V= 1,73L

Mr CO2= (1× Arc) + (2× Aro)
= (1× 12) + (2× 16)
= 12 + 32
= 44
mol= gr/Ar
= 3,4 gr/ 44
= 0, 078 liter gas CO2