berapa mol ca{oh}2 yang massanya3,7 gram?di ketahui Ar ca=40Aro=16Arh=1.cara jalanya dana jawabanya

dik Mr Ca(OH)2 = 40 + 2x16 + 2x1 = 74
n = m/mr
3,7/74 = 0,05 mol

STOIKIOMETRI

Mr Ca(OH)2
= Ar Ca + Ar O x 2 + Ar H x 2
= 40 + 16 x 2 + 1 x 2
= 40 + 32 + 2
= 74

n = m/Mr
n = 3,7 / 74
n = 0,05 mol.