tolong bantuannya kak diketahui f(x)=x√x+1/√x. fungsi f'(x)=

f(x) = x akar(x) + 1/akar(x)
= x . x^(1/2) + 1/(x)^(1/2)
= x^(1 + 1/2) + x^(-2)
= x^(3/2) + x^(-2)

f'(x) = 1 . 3/2 . x^(3/2 - 1) + 1 . -2 . x^(-2-1)
= 3/2 x^(1/2) + -2x^(-3)