Persamaan garis lurus yg melalui titik (-2,6)dan tegak lurus garis y=2x+4 adl

2x - y + 4 = 0
koefisien x = a
koefisien y = b
gradien1 (m1) = -a/b = -2/-1 = 2

syarat tegak lurus :
m1 × m2 = -1
2 × m2 = -1
m2 = -1/2

persamaan garis lurus :

(-2,6)
x1 = -2
y1 = 6

y-y1 = m2 (x-x1)
y-6 = -1/2 (x+2) <kedua ruas kali 2>
2y-12 = -1 (x+2)
2y-12 = -x -2
x+2+2y-12 =0
x+2y-10=0