150 ml larutan CH3COOH 0,1 m +100 ml larutan NaoH 0,1 m =ka CH3COOH=1*10*-5 Hitungla ph nya
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150 ml larutan CH3COOH 0,1 m +100 ml larutan NaoH 0,1 m =ka CH3COOH=1*10*-5
Hitungla ph nya
Hitungla ph nya
1 Jawaban
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1. Jawaban nugroho528
Mol CH3COOH = 150x0,1 = 15 mmol
Mol NaOH = 100x0,1 = 10
Mol CH3COOH sisa = 15-10 = 5 mmol
Mol CH3COONa ~ mol NaOH ~ 10mmol
[H+] = 10^-5 (5/10) = 5x10^-6
pH = 6 - log 5
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