jika 70 ml ch3cooh 0,1 m direaksikan dengan 100 ml naoh 0,05 m,ph larutan akhir adalah

Mol ch3cooh = 70x0,1 = 7 mmol
Mol naoh = 100x0,05 = 5 mmol
Mol ch3cooh sisa = 7-5 = 2 mmol
Mol ch3cooNa terbentuk = 5 mmol

[H+] = 10^-5 (2/5) = 4x10^-6
pH = - log (4x10^-6) = 6 - log 4
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