jika ²log7=a,maka 8log 49 adalah

8log 49 = 2³log 7² =(2/3) (²log7) = (2/3) a = 2a/3

²log 7 = a
[tex] log_{8}(7) = log_{ {2}^{3} }( {7}^{2}) \\ log({7}^{ \frac{2}{3} } ) = \frac{2}{ 3} log_{2}(7) = \frac{2}{3} a[/tex]