log 4basis 2+log16basis 2-log8basis 2 ------------------------------------------------------------ log125basis 25+log 1/5 basis 25+log 2basis 4

[tex]\displaystyle \frac{^2\log 4+^2\log 16-^2\log 8}{^{25}\log 125+^{25}\log \frac{1}{5}+^4\log 2} \\ \\ \frac{^2\log(4\times 16:8)}{^{25}\log(125\times \frac{1}{5})+^4\log 4^{1/2}} \\ \\ \frac{^2\log 8}{^{25}\log 25+\frac{1}{2}}=\frac{3}{1+\frac{1}{2}}=\frac{3}{^3/_2} \\ \\ 3\times\frac{2}{3}=2[/tex]