Tolong bantu jawab no 66 pakai cara, tolong

Mapel : Matematika
Bab :Persamaan Garis Lurus

(4,0)(0,3)

y - y1/y2 - y1 = x - x1/x2 - x1

y - 0/3 - 0 = x - 4/0 - 4

y/3 = x - 4/-4

-4y = 3(x - 4)

-4y = 3x - 12

y = -3/4x + 3

m1 = -3/4

Tegak Lurus

m1 × m2 = -1

-3/4 × m2 = -1

m2 = -1/1 × -4/3

m2 = 4/3

PGL B
(4,0)

y - y1 = m(x - x1)

y - 0 = 4/3(x - 4)

y = 4/3(x - 4) (×3)

3y = 4(x - 4)

3y = 4x - 16

0 = 4x - 3y - 16

(B)

Kelas 8 Matematika
Bab Persamaan Garis

(4, 0) dan (0,3)

m1 = (y2 - y1)/(x2 - x1)
m1 = (3 - 0)/(0 - 4)
m1 = 3/-4
m1 = -3/4

Tegak lurus

m1 . m2 = -1
-3/4 . m2 = -1
m2 = -1 . (-4/3)
m2 = 4/3

y - y1 = m (x - x1)
y - 0 = (4/3) . (x - 4)
3y = 4x - 16
4x - 3y - 16 = 0