Bila 0,1 gram NaOH dilarutkan dalam 250 ml air. Hitung harga pH larutan tersebut. (Ar Na=23, O=16 dan H=1)

dik: NaOH 0,1 gram
mr = 40
Vp = 250 ml

M = gr/mr × 1000/Vp
M = 0,1/40 × 1000/250
M = 0,0025 × 4
M = 0,01

[OH-] = valensi basa × M
[OH-] = 1 × 0,01
[OH-] = 10^-2

pOH = -log[OH-]
pOH = -log10^-2
pOH = 2

pH = 14-pOH
pH = 14-2
pH = 12