Berapa pH larutan jika 200 mL NH4OH 0,5 ditambah dengan 100 mL HCL 0,2 M (Kb NH4OH =1,8 kali 10 pangkat min lima

nNH4OH= 0,5x200= 100 ml mol= 1x10^-1
nHCL=0,2x100= 200 ml mol= 2x10^-1

OH= kb. mol basa/mol garam
=1,8.10^-5 x 1.10^-1/ 2x10-
=1,8.10^-5 x 0,5
=9x10^-6

POH= -log OH
=6-log 9

PH= 14-(6-log 9)
=8-log 9-0,95
=8-0,95
=7,05