bentuk sederhana dari 12 per akar 6 tambah akar 2 adalah

(12/√6) + (√2)
= 2√2 + √2
= 3√2

[tex] \frac{12}{ \sqrt{6} + \sqrt{2} } \times \frac{ \sqrt{6} - \sqrt{2} }{ \sqrt{6} - \sqrt{2} } \\ = \frac{12( \sqrt{6} - \sqrt{2} ) }{6 - 4} \\ = \frac{12( \sqrt{6} - \sqrt{2}) }{2} \\ = 6( \sqrt{6} - \sqrt{2} ) \\ = 6 \sqrt{6} - 6 \sqrt{2} [/tex]